![\"\"](\"http:\/\/wordpress.matbra.com\/wp-content\/uploads\/lm35.png\" "\\"lm35\\"")
<\/a>So to connect it to Arduino, you must connect VCC to Arduino 5V, GND to Arduino GND, and the middle pin you must connect to an Analog Pin, in my case I used A0.<\/p>\n
This projects doesn’t need any resistor or capacitor between the Arduino and the Sensor, so just connect it. The Arduino ADC has a precision of 10 bits, so in this case 5V \/ 2^10 = 5V \/ 1024, so 0.0049 is our factor. To get the temperature in Celsius, we get the value and calculate like this:<\/p>\n
Temperature = (pin * 0.0049)*100<\/p>\n
But why multiply by 100? PIN * 0.0049 will give the volts on port, if we multiply it by 1000 we will have millivolts on port, the sensor varies 10mV\/C so we need to divide it by 10 to get the temperature. On mathematics multiply by 1000 and divide by 10 is the same as multiplying by 100. Understand? [Add on 12\/12]<\/p>\n
And to have it on Fahrenheit, we need to make a conversion <\/p>\n
TemperatureF = (Temperature * 1.8) + 32.<\/p>\n
The arduino code that I used is: <\/p>\n
[code lang=”c”]
\nint analogPin = 0;
\nint readValue = 0;
\nfloat temperature = 0;
\nfloat temperatureF = 0;<\/p>\n
void setup() {
\n Serial.begin(9600);
\n} <\/p>\n
void loop() {
\n readValue = analogRead(analogPin);
\n \/\/Serial.println(readValue);
\n temperature = (readValue * 0.0049);
\n temperature = temperature * 100;
\n temperatureF = (temperature * 1.8) + 32;
\n Serial.print(“Temperature: “);
\n Serial.print(temperature);
\n Serial.print(“C “);
\n Serial.print(temperatureF);
\n Serial.println(“F”);
\n delay(1000);
\n}
\n[\/code]<\/p>\n
Hope you like it,
\nMatheus<\/p>\n
References: Hello, I’m starting to publish some experiments that I do with Arduino UNO\/Nano, sensors and other stuffs. Today I created a thermometer with LM35 sensor.…<\/p>\n
\nLM35 Datasheet<\/a>
\nArduino analog Read<\/a><\/p>","protected":false},"excerpt":{"rendered":"